New Invention: Hydraulic & Bearing Turbine Motor

BearingNEWS supports every person who is active in the field of research, development and new inventions.

The article below is a similar research/case study written by Mr. Salman Gürbüz, inventor and developer of  a new type of engine/motor.

PHYSICAL ANALYSIS

DESCRIPTION

THIS INVENTION CONSIST OF AN ENGINE THAT CONVERT POTENTIAL ENERGY INTO KINETIC ENERGY WITHOUT USING ANY FUEL. WITH THIS INVENTION; IT WILL BE POSSIBLE TO REACH TO THE FARTHEST POINTS OF THE WORLD WITHIN 10-15MINUTES. THE LIFE ON EARTH WILL BE CHEAPER BY 70 – 80 %. IT WILL BE THE BEGINNING OF A NEW ERA AND IT CAN BE USED EVERYWHERE.

UNIVERSITIES HAVE HIDDEN BEHIND PHYSICAL LAWS. THERE WERE THOSE WHO ACCEPTED THIS WAS POSSIBLE BUT NOBODY SUPPORTED WITH THE PENETRATION OF LIGHT; ENERGY BOTH DECREASE AND DISAPPEAR. THIS THEORY REPEAL THE FIRST LAW OF THERMODYNAMIC AND ENERGY CONVERSATION. THERE IS NO ELECTRON FLOW IN ELECTRIC BUT THERE IS A ENERGY PARTICLES. THE METALS THAT HAVE THE FEATURE TO PUSH EACH OTHER ALSO HAVE THE FEATURE TO ABSORB IT. TWO ELECTRON IN THE ORBIT OF COPPER IS VIBRATING THIS PARTICLE. THE MOVING FORCE IS VIBRATION THERE IS NO CURRENT. THE SPEED OF THE VIBRATION IS 300,000 KM PER HOUR.

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FIRST IMPELLENT

THE ENGINE IS ACTUATED BY AN ACCUMULATOR AS IT IS SEEN IN THE FIRST IMPELLENT FEEDBACK CIRCUIT. THIS CAN BE DONE BY AN HYDRAULIC ACCUMULATOR OR WITH ANOTHER WAY.

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FEEDBACK POWER

FEEDBACK POWER WILL RESEND THE LOST OIL BACK INTO THE ENGINE AFTER ENGINE RESTART. FOR THAT ACCUMULATOR IS BEING CHARGED BY MOVEMENT RECEIVED FROM ITS OWN SHAFT. THEREFORE ENGINE DO FEEDS ITSELF. WE WILL DRAW THE OIL THAT LEAKS OUT OF PRESSURE CHAMBER INSIDE THE MOTOR AGAIN BY USING THE CHANNELS LOCATED ON THE FRONT FACE OF COTTERS. THEN WE WILL COLLECT THE OIL IN A PLACE WITH THE HELP OF THE HOLES UNDERNEATH OF THE ENGINE AND WE WILL PUMP IT TO THE HIGH PRESSURE OIL CHANNEL BY USING THE HOLES BESIDE THE ENGINE. THE DIMINISHING OIL IN THE PRESSURE CHAMBER WILL BE SUPPLIED INSTANTLY. EVEN IF THE LEAKY OIL IS 1 TON PER HOUR ; A 1 KW PUMP WILL BE ENOY-UGH TO INCREASE IT TO 40 ATU.

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PHYSICAL ANALYSIS

THIS INVENTUON IS THE PHYSICAL ANALYSIS OF TWO COTTERS IN A PRESSURE CHAMBER. NUMBER OF COTTERS THAT LEANED ON THE INCLINED PLANE MIGHT BE MORE THAN ONE. AT THE SAME TIME IT IS ALSO POSSIBLE TO PROVIDE LINEER MOVEMENT BY USING CRANK METHOD. REQUIRED MEASUREMENT ARE PROVIDEN IN ABOVE FIGURES. APART FROM THAT THE COTTERS ARE APPROACHING TO THE CELL DIVISIONS BY 0,4 MM AND MOVE AWAY AFTER 0,4 MM. THIS IS ALSO ASSUMED IN CALCULATIONS.

PHYSICAL ANALYSIS IS THE NET RESULT:
I WILL REALIZE MY ANALYSIS BY USING THE VALUES AS :1000 REV/MIN AND 40 ATU(BAR)
FIRSTLY I WILL MAKE A PHYSICAL ANALYSIS BY ASSUMING THAT I LEANED THE MIDDLE OF THE COTTER ON THE INCLINED PLANE AND THEN I WILL REPEAT MY ANALYSIS
ACC TO GUIDANCE CHANNEL. HERE I WILL PUSH THE COTTERS BY LEANING THEM ON THE INCLINED PLANE WHICH MEANS I AM DISLOCATING WEIGHT. I AM DEDUCTING THE FORCE THAT USED FOR DRAWING THE COTTER IN TO THE PRESSURE CHAMBER FROM THE FORCE IN THE DIRECTION OF ROTATION. IF THE FORCE IN THE DIRECTION OF THE ROTATION AXIS INCREASE THAN THIS IS AN ENGINE. IF IT DOES NOT INCREASE THEN IT IS NOT. THE FORMULATE TO BE USED FOR DRAWING THE COTTER LEANED ON THE INCLINED PLANE INTO PRESSURE CHAMBER IS IN HIGH SCHOOL PHYSIC: LOAD * LOAD PATH = FORCE * FORCE PATH. THAT MEANS; IN ORDER TO UNDERSTAND THIS PROJECT, IT IS ENOUGH TO BECOME A HIGH SCHOOL GRADUATE. ACC. TO THIS; THE LOAD PATH IS 14 MM, AND FORCE PATH IS HYPOTENIUS AND IT IS: 21,05 MM. S1 AND S2 SURFACES ARE EQUALS AND 7.42 SQUARE CENTIMETER.
THEN YOU RECEIVE 296,8 KG PRESSURE AT 40 BARS. 296.8*14=FORCE * 21.05 THEN FORCE= 296,8*14/21.05;= 197,4 THIS IS THE REQUIRED FORCE TO DRAW THE COTTER WHICH IS LEANED ON THE INCLINED PLANE INTO THE PRESSURE CHAMBER. THE INCREASING FORCE IN THE ROTATION DIRECTION IS: 252 kg – 197,4 = 54,6 kg. ACCORDING TO THIS, IN EVERY PRESSURE CHAMBER, THE FORCE IS INCREASING BY 54,6 KG. INCREASING TOTAL ROTATION FORCE IS = 14 CHAMBERS * 54.6 KG = 764.4 KG.

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POWER CALCULATION

W= F*V
THEN W= 764,4 * 10 * 2 * 3,14*0,0735*1000/60= 58,8 KW.
IN THIS SYSTEM, WHATEVER THE REVOLUTION IS THE TORQUE IS FIXED.
POWER CALCULATION IN GUIDANCE CHANNEL, FOR THIS LET’S TRANSFER THE 252 KG FORCE IN THE DIRECTION OF ROTATION IN TO THE CHANNEL: 252KG * 73.5MM/104MM = 178,68 KG ROTATION FORCE IN EACH CHAMBER. IN HERE THE REQIRED FORCE FOR DRAWING ONE COTTER INTO THE PRESSURE CHAMBER IS CALCULATED ONCE AGAIN LOAD * LOAD PATH = FORCE * FORCE PATH 296.8 KG * 14 MM = FORCE * 26,8 MM THEN FORCE = 155,04 KG.
THEREFORE THE INCREASING FORCE IN THE DIRECTION OF ROTATION FOR EACH CHAMBER= 178,68 – 155.04 = 23.64 KG, IN TOTAL= 23.64 * 14 = 330.96 KG
THE FORCE INCREASE IN THE DIRECTION OF ROTATION.
POWER CALCULATION W= 330,96 * 10 * 2 * 3,14 * 0.104 * 100/60= 36 KW.
IN HERE THE COTTER IS BEING DRAWN FROM ITS MIDDLE PART WITH 297 KG FORCE AND IF WE TRANSFER THIS INTO CHANNEL BECAUSE OF MOMENT THEORY WE ARE ASSUMED TO USE LESS FORCE. UNFORTUNATELY I COULD NOT MAKE THIS PHYSICAL ANALYSIS CORRECTLY AND I CONSULTED TO UNIVERSITY LECTURER BUT THEY COULD NOT CALCULATE IT EITHER.THEREFORE INSTEAD OF MAKING FALSE CALCULATION, I PREFER NOT TO CALCULATE.

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Contact:
INVENTOR & PATENT OWNER
Salman GÜRBÜZ
ELECTRICAL ENGINEER
GSM: +90 505 462 87 42
E-mail: salmangurbuz@yahoo.com